Matematika Kuis +50: [tex]\begin{cases}p+q+r+s=96\\p+3=q-3 \\ q-3=3r\\3r=s\div3\end{cases}\\\\\sf2p-8q-4r+3s=[/tex] (A) 48 (B) 336 (C) 384 (D) -324 (E) 0

monarohanulv – March 07, 2023

Kuis +50:
[tex]\begin{cases}p+q+r+s=96\\p+3=q-3 \\ q-3=3r\\3r=s\div3\end{cases}\\\\\sf2p-8q-4r+3s=[/tex]
(A) 48 (B) 336 (C) 384 (D) -324 (E) 0

Jawaban:

E

Penjelasan dengan langkah-langkah:

p+q+r+s = 96

p+3 = q-3

p = q - 6

q - 3 = 3r

3r = q - 3

r = ⅓(q - 3)

3r = s/3

s = 9r

s = 9(⅓(q - 3)

s = 3q - 9

p+q+r+s = 96

q - 6 + q + ⅓(q - 3) + 3q - 9 = 96

5⅓q -(6+1+9) = 96

5⅓q = 96 + 16

16q/3 = 112

q = 3(112)/16

q = 21

p = 21 - 6

p = 15

r = ⅓(21-3)

r = 18/3

r = 6

s = 9(6)

s = 54

2p - 8q - 4r + 3s

= 2(15) - 8(21) - 4(6) + 3(54)

= 30 - 168 - 24 + 162

= 192 – 192

= 0

[answer.2.content]